Question

the 8th term of an A.P. is -10,10th term A.P is -16 find 15 term?​

Answer 1

$\huge \bold \pink{hello \: friend}$

It is given that,

8th term= -10

10th term= -16

16th term=?

Now,

a8= -10, a10=-16

So,

a+7d=-10------(1)

a+9d=-16------(2)

Subtracting eq(2) from (1),

-2d=6

-d=6÷2

-d=3

d=-3

Substituting d=-3 in (1),

a+7(-3)=-10

a-21=-10

a=-10+21

a=11

Therefore, a15=a+14d

=11+14(-3)

=11-42

=-31

Answer: -31

Answer 2

Step-by-step explanation:

Hello friend

d= -3

an = a +(n-1)d

= 11 +(14)-3

= 11-42

= -31

Therefor the 15th term of an A.P is -31