Question

The 8th term of an ap is 0. Prove that its 38th term is triple its 18th term

Answer 1

A = FIRST TERM, D = COMMON DIFFERENCE

8 TERM= 0

A - 7D =  0

A = 7D .........1

38 TERM = A - 37 D

18 TERM = A - 17 D

BTQ, A-37D = 3 (A-17D)

         7D - 37D= 3A- 51D

         -30 D = 21 D - 51D

                    = - 30 D

             D = 1...

A = 7

AFTER SOLVING THE EQUATION,

38TH TERM = A - 37 D = 7 - 37 = - 30

18TH TERM = A - 17 D = 7 - 17 = -10

BY SEEING THE 18 AND 38 TERMS , IT IS CLEAR TO US THAT THE 38 TH TERM IS TRIPLE OF ITS 18 T6H TERM..... PROVED.....

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