The 8th term of an ap is 17 and the 19 term is 39 find the 25 tetm
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8th term = a+7d = 17 ----(1)
19th term = a+18d = 39 -----(2)
solving (1) and (2)
a+7d = 17
a+18d = 39
(-) (-) (-)
---------------------
-11d= -22
d = 2
sub d=2 in 1-
a+7*2 = 17
a = 3
a_25 = a+(25-1) d
a_25 = 3+24*2
hence, a_25 = 51
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