Question

The 8th term of an ap is 37and its12th
term is 57 find the ap

Answer 1

given a8=37
a12=57
so
a8=a+(n-1)×d
37 =a+(8-1)×d
37 =a+7d. ..........(1)
a12=a+(n- 1)×d
57= a+11d. ..................(2)
SUBTRACTING 1 FROM 2
WE GET
57= a+11d
37 =a+7d
20=4d
5=d
substituting the value of d in equation 1 we get
37=a+7×5
37=a+35
2=a


so now the ap will be
2,7,12,17...

Answer 2

a8=37 ,a11=57
a+7d=37
-a+11d=57
=-5d=-20
=d=4
a+6(4)=37
a+24=37
a=37-24
a=13