The 8th term of an AP is 5 times the 3rd term while the 7th term is 9 greater than the first term write the first 9 terms of the AP
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Answer:
-9/8,3/8,15,8,27/8,39/8,51/8,63/8,75/8,87/8......
Step-by-step explanation:
T8=5T3
a+7d=5(a+2d)
a+7d=5a+10d
4a=-3d
T7-T1=9
a+6d-a=9
6d=9
d=3/2
a=-9/8
Here the required AP is
-9/8,3/8,15/8,27/8,39/8,51/8,63/8,75/8,87/8......
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