Question

the 8th term of an ap is half of its second term and the 11th term exceeds one third of its fourth term by 1 find the 15th term​

Answer 1

A8=a+7d=a+d/2                 2(a+7d)=a+d             2a+14d= a+d         2a-a+14d-d=0     a+13d=0.       ...... (i)

A+10d=a+3d/3+1  A+10d=(a+3d+3)/3  3(a+10d)=a+3d+3  3a-a+30d-3d-3=0       2a+27d=3.... (ii)  Solve (i)&(ii)  Eq(i) multiply by 2 2a+26d=0......(iii)       2a+27d=3.......(iv)

Solve (iii) & (iv)  D=3

Put d in (i)  A+39=0  A= -39****   D=3

A15=a+14d       =.  - 39+14(3)=.  - 39+42=. 3

A15 is 3                I hope this answer is helpul to you my dear