The 8th term of an AP is half the 2nd term and the 11th term exceeds 1/3 of the 14th term by 1.Find the 15th term
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Answer:
A8=1/2 a2
A+7d=1/2 (a+d)
2a+14d=a+d
A=-13d
A11= 1/3 (a14) +1
A+10d=1/3 (a+13d) +1
3a+30d=a+13d+1
3(-13d)+30d=(-13d)+13d+1
-39d+30d=1
-9d=1
D=-1/9
=>a=-13(-1/9) =13/9
A15= 13/9+ 14(-1/9)
=(13-14)/9=-1/9
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