the 8th term of an ap is zero prove that its 38 term is triple of its 18 term
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a8 = 0
a + 7 d = 0
a = - 7d
a38 = 3 a18
a + 37d = 3 ( a + 17d )
-7d + 37 d = -21d + 51d
30d = 30d
hence proved
a + 7 d = 0
a = - 7d
a38 = 3 a18
a + 37d = 3 ( a + 17d )
-7d + 37 d = -21d + 51d
30d = 30d
hence proved
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