The 8th term of an ap is zero prove that its 38th term is triple its 18th term
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Answered by
3
Answer:
Step-by-step explanation:
"a(8) = a+7d, where a is the first term and d is the common difference.
a+7d=0
a=-7d
A +7d= 0
a= -7d
As is the 38th term
a₃₈ = a +37d
= -7d + 37d
= 30d
a(38) = a+37d = -7d+37d = 30d
a(18)=a+17d = -7d+17d = 10d
30 d = 3 times 10 d
38th term is triple its 18th term
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Answered by
0
Answer:
T38= 30d
T17=. 10d
Explanation is in photos
I hope this helps you
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