Question

the 8th term of an AP is zero. Prove that its 38th term is triple its 18th term.

Answer 1

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Answer 2

given 8th term of an A.P i.e, a+(8-1)d=0
                                                  a+7d=0
                                                   a=-7d
18th term is a+(18-1)d
                     =a+17d
                     =-7d+17d
                     =10d (from above)
38th term is a+(38-1)d
                     =a+37d
                     =-7d+37d
                     =30d
comparing 18th amd 38th term
             t38=3(t18)
             30d=3(10d)
             30d=30d
hence we proved that 38th term is triple its 18th term.