The 8th term of an AP is zero. Prove that its 38th term is triple of its 18th term.
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Answer:
Step-by-step explanation:
a8=0
a+7d=0
a=-7d
a38=a+37d
= -7d+37d
=30d
a18=a+17d
= -7d+17d
=10d
triple of a18= 3*10d
=30d
Therefore it is proved that a38=3*a18
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