The 8th term of an AP is zero prove that its38th term is triple its 8th term
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T(8)=0
so, a+7d=0
so, a=-7d
now T(38)=a+37d=-7d+37d=30d
the question u just asked is a bit sarcastic in a way that it is actually asking the 38th term to be thrice of its 8th term which means it wants its 38th term to be zero and in an ap it will never happen that the same number like 0 or whatever will be the value of its two terms
so, a+7d=0
so, a=-7d
now T(38)=a+37d=-7d+37d=30d
the question u just asked is a bit sarcastic in a way that it is actually asking the 38th term to be thrice of its 8th term which means it wants its 38th term to be zero and in an ap it will never happen that the same number like 0 or whatever will be the value of its two terms
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