The 8th term of an arithmetic sequence is53 and 15th term is 102 find the algebraic expression
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Step-by-step explanation:
Hey mate , here is your answer
From the QUESTION we have , a sequence in AP .
Let the first term be a and common difference be d .
Since , 8th term is equal to 53 and 15th term is equal to 102 .
So , according to QUESTION , we have
a + 7 d = 53
a + 14 d = 102
→ Required algebraic expression
2a + 21d = 155
More work :-
Solving the equation , we get
7 d = 49
→ d = 7 .
a + 49 = 53
→ a = 4 .
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