Question

the 8th term of the G.P 9,3,1,_​

Answer 1

Step-by-step explanation:

T8=ar^(n-1)

= 9(1/3)^7

mark as brilliant

Answer 2

Answer:

9, 3, 1...

here, first term (a) = 9 and common ratio (r) = 1/3

therefore, 8th term of the GP = ar⁷ = 9×(⅓)⁷

= 1/3⁵ = 1/243

Note :

n th term of a GP =

$a {r}^{n - 1}$