Question

The
9 gas
out
OF
valume of
of 0.02016 gm of
at
NITP 18 224 Me. find
the weight OF
1 I molecule
the gas.​

Answer 1

Explanation:

Let M be the molar mass of the gas.

The number of moles of the gas, n=

M

2.9

.

The volume of the gas is V=

P

nRT

.

V=

MP

2.9R×368

The number of moles of dihydrogen are n

′

=

2

0.184

=0.092

The volume of dihydrogen gas is =

P

0.092×R×290

.

At same pressure P, the volume of gas is equal to volume of dihydrogen.

0.092R×290=

M

2.9R×368

M=

0.092×290

2.9×368

=40

Thus, the molar mass of the gas is 40g/mol.