Question

The 99% confidence interval for mean is (12,16). Then, find the value of sample mean and margin of error


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Answer 1

→ sample mean = ( lower limit + upper limit) / 2 = (12 + 16)/2 = 28/2 = 14 . therefore, → margin of error = (upper limit - lower limit) / 2 = (16 - 12)/2 = 4/2 = 2 .

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Answer 2

Explanation:

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