the 9th term of an ap is -4 and its 13th term is minus 16 find the AP
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1
Answer:
Step-by-step explanation:
9th term of an A.P=-4
a₉=-4
a+8d=-4 --->(1)
13th term of an A.P=-16
a₁₃=-16
a+12d=-16 --->(2)
eq(2)-eq(1)
⇒a+12d-1-8d=-16+4
⇒4d=-12
⇒d=-3
Substitute d in eq(1)
⇒a+8(-3)=-4
⇒a=-4+24
⇒a=10
a₁=a=10
a₂=a+d=10-3=7
a₃=a₂+d=7-3=4
a₄=a₃+d=4-3=1
...
Hence the A.P is 10,7,4,1,......
Answered by
1
Answer:
20 17 14 11........
Step-by-step explanation:
use the formulas of arithmetic progression for n= 9 and n= 13 and solve the equation.
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