the 9th term of an ap is equals to 6 time of its second term if the fifth term is 22 find the AP
Answers
Answer:
the ap is:2, 7, 12, 17...
Detailed Solution:
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EXPLANATION.
- GIVEN
9th term of an Ap is equal to 6 times of its
2nd term.
5th term is 22
TO FIND THE AP.
Formula of Nth terms of an Ap.
=> An = a + ( n - 1 ) d
=> case = 1
=> T9 = 6 ( T2)
=> a + 8d = 6 ( a + d)
=> a + 8d = 6a + 6d
=> 8d - 6d = 6a - a
=> 2d = 5a ...... (1)
=> case = 2
=> T5 = 22
=> a + 4d = 22
=> a = 22 - 4d ........ (2)
From equation (1) and (2) we get,
put the value of equation (2) in equation (1)
we get,
=> 2d = 5 ( 22 - 4d )
=> 2d = 110 - 20d
=> 22d = 110
=> d = 5
put the value of d = 5 in equation (1)
we get,
=> 2 ( 5 ) = 5a
=> 10 = 5a
=> a = 2
Therefore,
Tn term = a + ( n - 1 ) d
Algebraic expression of an Ap
=> An = 2 + ( n - 1 ) 5
=> An = 2 + 5n - 5
=> An = 5n - 3
Therefore,
An = 5n - 3
put n = 1 we get,
=> 5(1) - 3 = 2
put n = 2 we get,
=> 5(2) - 3 = 7
put n = 3 we get,
=> 5(3) - 3 = 12
put n = 4 we get,
=> 5(4) - 3 = 17