The 9th term of an ap is equals to the seven times the second term of 12th term exceeds five time the third by 2 find a and b
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Answer:
a=1 , d=6
Step-by-step explanation:
9th term=7(2nd term)
a+8d=7(a+d)
a+8d=7a+7d
d=6a -----eq1
12th term=5(3rd term)+2
a+11d=5(a+2d)+2
a+11d=5a+10d+2
4a+2=d ------eq2
equating eq1 and eq2, we get
4a+2=6a
6a-4a=2
2a=2
a=1
from eq1 6a=d
d=6(1)
d=6
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