Question

The 9th term of H.P 6, 4, 3, ....... is
answer is 6/5
please send me solution ​

Answer 1

Answer:

N9=6+(9-1)-2

N9=6+8×-2

N9=6+(-16)

N9=6-16

N9=-10

this will be the answer.

If you are satisfied plz mark it as a branliest because its urgent.

Answer 2

Given,

H.P. = 6, 4, 3,    

To Find,

The 9th term =?

Solution,

We can solve the question as follows:

We have to find the 9th term of the given harmonic progression. A harmonic progression is a set of numbers that is formed by taking the reciprocal of an arithmetic progression.

Therefore, converting the H.P. to A.P. by taking the reciprocal of every term,

A.P. = $\frac{1}{6}, \frac{1}{4} ,\frac{1}{3}$

Now,

The nth term of an A.P. is given as,

$T_{n} = a + (n-1)d$

Where $a =$ first term

           $n =$ the nth term

           $d =$ common difference

From the A.P.,

$a = \frac{1}{6}$

$n = 9$

$d = \frac{1}{4} - \frac{1}{6} = \frac{1}{12}$     (The difference between two consecutive terms)

Substituting the values in the above formula,

$T_{n} = \frac{1}{6} + (9-1)\frac{1}{12}$

     $= \frac{1}{6} + \frac{8}{12}$

    $= \frac{1}{6} + \frac{4}{6}$

   $= \frac{5}{6}$

Now,

the nth term of an H.P. is equal to the reciprocal of the nth term of the corresponding A.P.

Therefore,

$T_{n}$ of an H.P. = $\frac{1}{T_{n}}$

                     $= \frac{1}{\frac{5}{6} }$

                     $= \frac{6}{5}$

Hence, the 9th term of the H.P. is 6/5.