Question

the A(1, 1) B(3, 2) and C(5, 3) CANNOT BE THE Vertices of the triangle ABC justify​

Answer 1

Answer:

the given coordinates,

A(1,1)

B(3,2)

C(5,3)

Now,

area of the triangle ∆ABC

\begin{gathered} = \frac{1}{2} | \binom{1}{1} \binom{3}{2} \binom{5}{3} \binom{1}{1} | \\ = \frac{1}{2} ((2 + 9 + 5) - (3 + 10 + 3)) \\ = \frac{1}{2} (16 - 16) \\ = \frac{1}{2} \times 0 \\ = 0\end{gathered}=21∣(11)(23)(35)(11)∣=21((2+9+5)−(3+10+3))=21(16−16)=21×0=0

the area of the triangle was 0.

so it can only explain that no triangle was formed.

so these are not the vertices of a triangle