the
A
copper wire has a resistance of o.6 ohms.
Another copper wire of the same mass as the 1st one is doubled in length of the 1st. find the resistance of the second wire?
One in double in length
the 1st
find the resistance of the second wire?
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Explanation:
resistivity=r
length=l
area =a
resistance=R
1st wire
R=r2l/a=0•6
2nd wire
0•6/2=rl/a
0•3 ohm is the answer
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