Question

the a+ib form of (8+7i)(8-7i) is
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Answer 1

Answer:

$113 + 0i$

Step-by-step explanation:

we have,

${a }^{2} - {b}^{2} = (a + b)(a - b)$

so,

$(8 + 7i)(8 - 7i) = {8}^{2} - {(7i)}^{2}$

$= 64 + 49$

$= 113$

a+ib from is 113+0i