Question

The A.M. of a set of 10 numbers is 38. If two numbers of the set namely 35 and 45 are discarded, the A.M. of the remaining set of numbers is *

Answer 1

Answer:

NEW A.M = 37.5

Step-by-step explanation:

A.M =

$\frac{sum \: of \: all \: obs}{total \: no \: of \:outcomes }$

A.M =

$38 = \frac{x}{10}$

$x = 380$

if 35 and 45 are discarded, then total number of outcomes become 8 and sum of all observations become 380 – (35+45)

ie.,

$am \: = \frac{300}{8} = 37.5$

Answer 2

ANSWER:. 37.5

EXPLANATION:

A.M. = [(∑xi)/50] = 38 ⇒ ∑xi = 1900 and n = 50 New (∑xi)new = 1900 – 55 – 45 = 1800 and n' = 48 ∴ (A.M.)new = [(∑xi)new/n'] = [(1800)/48] = 37.5.