Question

The A.M of square of first '2n' natural numbers is​

Answer 1

Answer:

Step-by-step explanation:

As you know,

Sum of the squares of n natural numbers can be found by a formulae :

S = n*(n+1)*(2n+1)/6

So, average of sum of squares of first n natural numbers will be :

Average = (Sum of squares of n natural numbers) / (n)

But, in the question, it is asked for 2m natural numbers.

So, replace 'n' with '2m'.

We get,

AVERAGE = {m*(m+1)*(2m+1)/6 } /2m

∴ AVERAGE = (m+1)*(2m+1)/12

Answer 2

Answer:

average of 2n natural number is

1+2+3+•••••+2n÷n

n(2n+1)÷2n

2n+1÷2