The A.P. in which 4th term is –15 and 9th term is –30. Find the sum of the first 10 numbers.
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Hello ,
a+3d = -15 ---------(1)
a+8d= -30 (-)
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-5d = 15
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d= -3
put d= -3 in equation (1)
a- 9 = -15
a = -6
sn = n/2 (2a+(n-1)d)
s10 = 10/ 2 (2 x -6 + 9(-3))
= 5( -12 -27)
= 5( -39)
= -195
Good luck
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