The A.P of 5 have 55 terms find the mean of the sequence
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Let the terms in the arithmetic progression be a,a+d,a+2d,a+3d and a+4d .
Given the sum of these terms
=5a+10d=55
Hence a+2d=11
So T3=11 also given t4=5+t1+t2
Hence a+3d=5+a+a+d
So 2d=5+a
Adding a on both sides we get
a+2d=5+2a
But a+2d=t3=11
Hence 11=5+2a
So a=3
Also 2d=5+a hence d=4
Hence the series will be
3,7,11,15,19
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