Question

The a value of k for which the system
of equations

x + 2y = 5
3x+ky+15=0
​

Answer 1

Answer:

y = 30 / (6-k)

x   = - (30+5k) / 60

Step-by-step explanation:

(The question is incomplete but you can always find the value of k having given the values of x & y from the answer given)

given x+2y = 5

=> x = 5-2y

also given that

3x +ky+15 = 0

ie, 3(5-2y) + ky + 15 = 0

=> 15-6y+ky+15=0

=> y(6-k) = 30

=> y = 30 / (6-k)

also x = 5 - 2( 30 / (6-k) )

          = 5 - (60/(6-k))

          = [ (30-5k) - 60] / 60

       x   = - (30+5k) / 60