Question

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Answer 1

Given: triangle ABC and triangle DBC are on the same base BC. To prove: area of triangle ABC/area of triangle DBC= AO/DO  Construction:draw a perpendicular to BC and DF perpendicular to BC. Proof: In triangle AOE and DOF AOE=DOF(V.O.A) AEO=DEO(each 90) Triangle AOE is similar to Triangle DOF by AA similarity. AO/DO=AF/DF Area triangle ABC/Area triangle DEF =1/2*BC*AE/1/2*BC*DF=AE/DF=AO/DO.