The absolute enthalpy of neutralisation of the reaction: will be:
(a) -57.33 kJ mol⁻¹
(b) greater than -57.33 kJ mol⁻¹
(c) less than -57.33 kJ mol⁻¹
(d) 57.33 kJ mol⁻¹
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hey mate..... the answer is
(a) -57.33 kJ mol−1
(a) -57.33 kJ mol−1
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