The absolute reflective index of a water is 1.36. What is the velocity of light in water ? ( Velocity of light in vacuum = 3×10⁸ m/s )
Answers
Answer:
The velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10
8
s
m
Given,
The absolute refractive index of water = 1.36 and
velocity of light in vacuum= 3\times 10^8 \dfrac{m}{s}3×10
8
s
m
To find, the velocity of light in water = ?
We know that,
The velocity of light in water =\dfrac{velocity of light in vacuum}{The absolute refractive index of water}
Theabsoluterefractiveindexofwater
velocityoflightinvacuum
=\dfrac{3\times 10^8 \dfrac{m}{s}}{1.36}=
1.36
3×10
8
s
m
=2.205\times 10^8\dfrac{m}{s}=2.205×10
8
s
m
The velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10
8
s
m
Hence, the velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10
8
s
m
Explanation:
Given,
The absolute refractive index of water = 1.36 and
velocity of light in vacuum= 3\times 10^8 \dfrac{m}{s}3×10
8
s
m
To find, the velocity of light in water = ?
We know that,
The velocity of light in water =\dfrac{velocity of light in vacuum}{The absolute refractive index of water}
Theabsoluterefractiveindexofwater
velocityoflightinvacuum
=\dfrac{3\times 10^8 \dfrac{m}{s}}{1.36}=
1.36
3×10
8
s
m
=2.205\times 10^8\dfrac{m}{s}=2.205×10
8
s
m
=2.205\times 10^8\dfrac{m}{s}=2.205×10
8
s
m
The velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10
8
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Answer:
answer is 8
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