Question

The absolute refractive index of a material is √2 then its critical angle is . . . . ​

Answer 1

Answer:

Now, n =2 , therefore , sinC=2 1 Then, C =45∘

Answer 2

Answer:

45°

Explanation:

Given :

Refractive index = √2

To find :

Critical angle

Solution :

We know that, sin of critical angle is reciprocal of refractive index

$\boxed {\sin c = \dfrac{1}{\mu}}$

where, c = critical angle and μ = refractive index

Substituting the values, we get,

$\longmapsto \sin c = \dfrac{1}{\sqrt{2} }$

We know that,

$\sin 45^{\circ} = \dfrac{1}{\sqrt{2} }$

Thus,

$\implies \sin c = \sin 45^{\circ}$

$\implies \boxed{\mathbf{c = 45^{\circ}}}$

Hope it helps!!