the absolute refractive index of benzene 1.5. what is its critical angle
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Given :
absolute refractive index of benzene = 1.5
critical angle = ?
Formula:
n=1/sinc
⇒sinc=1/n⇒1/1.5⇒10/15⇒0.666
sinc=0.666
∴c=42⁰
absolute refractive index of benzene = 1.5
critical angle = ?
Formula:
n=1/sinc
⇒sinc=1/n⇒1/1.5⇒10/15⇒0.666
sinc=0.666
∴c=42⁰
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