Question

the absolute refractive index of water 4/3. what is the critical angle​

Answer 1

Answer:

Explanation:

N = $\frac{1}{Sin C}$

Sin C = $\frac{1}{N}$

Sin C = $\frac{1}{\frac{4}{3} }$

Sin C = $\frac{3}{4}$

Sin C = Sin 48.59

C = 48.59

⇒ Critical angle is (c)=48.59°

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Answer 2

N=

sinC

1

sinC=

n

1

sinC=

(

3

4

)

1

sinC=

4

3

sinC=sin48.59

C=48.59

critical angle is (c)=48.59

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