Question

The absolute refractive index of water is 1.42 what is the velocity of light in water?

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

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Explanation:

The velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10

8

s

m

Explanation:

Given,

The absolute refractive index of water = 1.36 and

velocity of light in vacuum= 3\times 10^8 \dfrac{m}{s}3×10

8

s

m

To find, the velocity of light in water = ?

We know that,

The velocity of light in water =\dfrac{velocity of light in vacuum}{The absolute refractive index of water}

Theabsoluterefractiveindexofwater

velocityoflightinvacuum

=\dfrac{3\times 10^8 \dfrac{m}{s}}{1.36}=

1.36

3×10

8

s

m

=2.205\times 10^8\dfrac{m}{s}=2.205×10

8

s

m

The velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10

8

s

m

Hence, the velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10

8

s

m