The absolute refractive index of water is 4/3. find critical angle.
Answers
Answered by
8
Absolute refractive index of water
(n) = 4/3
Critical angle (c) = ?
Sin C = 1/n
Sin C = 3/4 = 0.75 = Sin 48 o 36 I
C = 48 o 36 I
(n) = 4/3
Critical angle (c) = ?
Sin C = 1/n
Sin C = 3/4 = 0.75 = Sin 48 o 36 I
C = 48 o 36 I
Prakashroy:
Is it helpful?
Answered by
4
I hope you got it...........
Attachments:
Similar questions