Question

The absolute refractive index of water is 4/3. find critical angle.

Answer 1

Given, the absolute refractive index of water is said to be 4/3.


Assume, the critical angle is said to b C. Stating, Snell’s Law, C is equal to sin^-1(1 divided by refractive index) C is equal to sin^-1(3 divided by 4) C is equal sin^-1(0.75) C is equal 48.59°

Answer 2

Heya ✴✴✴

Answer :-

The absolute refractive index of water = 4/3

critical angle c then
sin c = 1/n
sin c = 1/4/3 = 3/4

c = sin^-1 3/4 = 48°30' = 48.5°

C = 48.5°

Hope this helps