The absolute refractive index of water is 4/3. find critical angle.
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Given, the absolute refractive index of water is said to be 4/3.
Assume, the critical angle is said to b C. Stating, Snell’s Law, C is equal to sin^-1(1 divided by refractive index) C is equal to sin^-1(3 divided by 4) C is equal sin^-1(0.75) C is equal 48.59°
Assume, the critical angle is said to b C. Stating, Snell’s Law, C is equal to sin^-1(1 divided by refractive index) C is equal to sin^-1(3 divided by 4) C is equal sin^-1(0.75) C is equal 48.59°
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Heya ✴✴✴
Answer :-
The absolute refractive index of water = 4/3
critical angle c then
sin c = 1/n
sin c = 1/4/3 = 3/4
c = sin^-1 3/4 = 48°30' = 48.5°
C = 48.5°
Hope this helps
Answer :-
The absolute refractive index of water = 4/3
critical angle c then
sin c = 1/n
sin c = 1/4/3 = 3/4
c = sin^-1 3/4 = 48°30' = 48.5°
C = 48.5°
Hope this helps
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