the absolute refractive index of waters is 4/3. what is the critical angle?
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R.I. = 1/sinA
Sin A=3/4
A = 48°
Critical angle of water is 48°
sintheta = mu1/mu2 - formula for critical angle
mu1 - refractive index of the medium from where the incident ray strikes & gets refracted
mu2 - refractive index of the medium from where the refracted ray travels through.
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AiyraBaig09:
Sin A=3/4=0.75
And sin 48 is aproximately 0.75
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