Question

The absolute refractivw index of water is 4/3.What is the critical angle?​

Answer 1

Answer:

48.59°

Explanation:

N= 1/sinC

sinC= 1/n

sinC= 1/4/(4/3)

sinC= 3/4

sinC=sin48.59

C=48.59

critical angle is (c)=48.59

0

Answer 2

Explanation:

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