the accelaration of upper block
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RJRishabh:
is it rigjt
right ???
nope
what is ans
5m/s^-2
5m/s square sry
i gave my solution, check it :D
Answers
Answered by
1
Maximum force that can be applied so both blocks move together is u(m+M)g = 48N but here force is lesser than that so both blocks move together,
Acceleration is given by F/(m+M)=30/6 =5m/s square
bro what is the use of that 48 N ??
See 48N is the maximum force that can be applied on the lower block for which both blocks move together. If force applied wouldve been more than 48 N then the two blocks will have different accelerations
ohhh yeah becoz static friction = fk × Normal
sry coeff of static friction × normal
thank you people☺️
I just checked the static friction being more than 30 N ... so i assumed both bodies as a single one
Answered by
0
here is your answer !!!
if we assume w
both bodies as a single one..
F = ma
a = 30 / 60N
a= 30 / 6 kg
a = 5 m / sec sq.
Since the velocity of 2kg block will be the same as the 5kg block.. becoz the static frictional force is less than 30 N
if we assume w
both bodies as a single one..
F = ma
a = 30 / 60N
a= 30 / 6 kg
a = 5 m / sec sq.
Since the velocity of 2kg block will be the same as the 5kg block.. becoz the static frictional force is less than 30 N
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