The acceleration(a) of a particle in one dimensional motion is related to time (t) as
a=2-t. If the particle is starts from rest from origin at time t=0 then the position
of the particle at time t= 6 sec is
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This question involves integration .
Integration of acceleration gives velocity and integration of velocity gives displacement
Therefore 2° integration of acceleration will give displacement.
D = f(t) = t² - t³/6 from t=0 to t=6
=6²-6³/6
=6²-6²
= 0
I hope I am right . ☮️
saitharun1199:
thanks it was the right answer
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