Question

the acceleration a of moving body from rest is 2(t-1) then velocity at 5 seconds will be
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Answer 1

Explanation:

All we need is distance and to change start time to 0. Use 5-0 as change in time because we have the starting velocity as 0 at zero seconds, we would need to know the velocity at 1 second to correctly solve it.

If you want to keep the problem at 5-1, solve for 1-0 as change in time first, then solve for change in time of 5-1, but best to use one equation so we will do 5-0 for time, ie…

Find the FINAL velocity with distance displaced that we need to answer question because Velocity = distance/ time. Use final distance displaced and to put in a value for the top part of acceleration equation-

We need v2, use v=distance/time when time is 5sec

a= V2 -V1 / t2-t1

t2 is 5 and t1 is 0 , so 5-0 is 5

a= (V2-0)/5

For layman's sake, we will assume it's in metric unts, in which acceleration is in units of m/s 2. (2 means square

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