The acceleration due to gravity at a height h
above the surface of the earth (radius = R) is given by
g'=g(1-2h/R)
If h<<R, then show that: g'=g(1-2h/R)
Plz explain with the use of binomial theorum.
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Answered by
0
Answer:
Value of gravitational acceleration at a height h above th earth's surface is given by g
′
=g(
R+h
R
)
2
∴
4
g
=g(
R+h
R
)
2
Or
R+h
R
=
2
1
Or h+R=2R
⟹ h=R
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