the acceleration due to gravity at a place is 0.2m×s-2.find its height above the earth surface
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it is given that gravity at a place is 0.2m/s^2 and we lnow acceleration due to gravity on the surface of the earth is 9.8m/s^2.
so,
we will apply formula of g at place/ g on earth= (radius/ radius+ height)^2
o.2/9.8= (r/r+h)^2
1/49=(r/r+h)^2
1/7=r/r+h
7r=r+h
6r=h
as we know that radius of earth=6400km
so, 6*6400=h
hence,h=38400 km
so,
we will apply formula of g at place/ g on earth= (radius/ radius+ height)^2
o.2/9.8= (r/r+h)^2
1/49=(r/r+h)^2
1/7=r/r+h
7r=r+h
6r=h
as we know that radius of earth=6400km
so, 6*6400=h
hence,h=38400 km
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