Question

The acceleration due to gravity at the moon's surface is 1.67 m/s². If the radius of the moon is 1.74 × 10^6 m, calculate the mass of the moon. Use the known value of G.​

Answer 1

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$\huge\mathfrak{Solution:-}$

⏩ Here,

*G= 6.67 × 10^-11 Nm²/kg²,

*g= 1.67 m/s²,

*R= 1.74 × 10^6 m.

Mass of the moon is,

M= gR²/G

= 1.67 × (1.74 × 10^6)²/6.67 × 10^-11

= 7.58 × 10²² kg. Ans.

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Answer 2

Answer:

7.58×10^22 kg

Given:

Moon's surface=1.67 m/s^2

Radius of moon=1.74×10^6 m

G=6.67×10^-11

To find:

Mass of the moon

Solution:-

Givenradius=1.74×10^6,surface=1.67 and G=6.67×10^-11

Now

We know that

G=gR^2/G

=1.67(1.74×10^6)^2/6.67×10^-11

=7.58×10^22 kg

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Mass of the moon=7.58×10^22 kg