Question

the acceleration due to gravity bear the surface of a planet of Radius 'R' and Density 'D' is proportional to​

Answer 1

Question:

The acceleration due to gravity near the surface of a planet of radius 'R' and density 'd' is proportional to __________.

Answer:

The acceleration due to gravity near the surface of a planet of radius 'R' and density 'd' is proportional to Rd.

Step by step solution:

Acceleration due to gravity is given by g =

$\frac{GM}{R {}^{2} } \: where \:M \: = density \times volume \\ = d \times \frac{4}{3}\pi \: R {}^{2} \\ now \: g = \frac{GM}{R} {}^{2} = \frac{4}{3} \pi \: GR \\ = g = Rd$

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