Question

The acceleration due to gravity on a planet A is
9 times the acceleration due to gravity on planet
B. A man jumps to a height of 2 m on the surface
of A. What is the height of jump by the same
person on the planet B?
(1) 2/9 m
(2) 18 m
(3) 6 m
(4) 2/3 m​

Answer 1

Explanation:

h2 = 9h = 9(2) 

so option (2).18m...

Answer 2

Answer:

ANSWER IS 18

PLEASE MARK ME AS BRAINLIEST

AND IF MY ANSWER IS CORRECT THEN PLEASE INBOX ME IF POSSIBLE ✌✌✌❤

Explanation:

It is given that acceleration due to gravity on plane. A is 9 times the acceleration due to gravity on planet B i.e.,

gA=9gB ...(i)

From third equation of motion 

v2=2gh ...(ii)

At planet A,hA=2gAv2 ...(ii)

At planet A,hB=2gBv2 ...(iii)

Dividing Eq. (ii) by Eq. (iii) we have 

hBhA=9gA9gB

From Eq. (i), gA=9gB

∴hBhA=9gA9gB=91

or hB=9hB=9×2=18m