The acceleration due to gravity on a planet is
1.96 m/s2. If it is safe to jump from a height of
3 m on the earth, the corresponding height on the
planet will be
(1) 3 m
(2) 6 m
(3) 9 m
(4) 15 m
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Answer:
Initial velocity = u = 0
acceleration = 9.8
vertical distance = 3m
final velocity = v = 0
so,
v² - u²= 2as
v² - 0 = 2 x 9.8 x 3
v= 7.7
in the 2nd situation;
u = 0
v= √58.8
a= 9.8
applying the same formula
58.8 - 0 = 2 x 9.8 x s
s = 1.5 m
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