The acceleration due to gravity on the Earth’s surface is ‘g’. If the acceleration due to gravity on the surface of another planet, whose mass is four times the earth’s mass and radius is twice the earth’s radius is ng, find the value of n.
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Hello Dear.
Here is your answer---
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For the Earth,
Let the Mass of the Earth be m and the radius of the earth be r.
Acceleration due to the gravity on Earth = g
Using the Formula,
g = Gm/r² --------------------------eq(i)
Where G = Gravitation constant
= 6.67 × 10⁻¹¹ Nm²/kg²
For the Another Planet,
Mass = 4 × Mass of the earth
Mass = 4 × m
Radius = 2 ×Radius of the Earth
= 2 × r
Acceleration due to the Gravity = ng
Now again using the formula,
Acceleration due to gravity = G × Mass/Square of the radius
⇒ ng = G × 4m/(2r)²
ng = G × 4m/4r²
ng = G × m/r² -------------------------------eq(ii)
Putting the Value of g from eq(i) in the above equation,We get,
n × (G × m/r²) = G × m/r²
⇒ n = 1
Thus, the value of n is 1.
→→→→→→→→→→→→
Hope it helps.
Have a Marvelous Day.
Here is your answer---
→→→→→→→→→→
For the Earth,
Let the Mass of the Earth be m and the radius of the earth be r.
Acceleration due to the gravity on Earth = g
Using the Formula,
g = Gm/r² --------------------------eq(i)
Where G = Gravitation constant
= 6.67 × 10⁻¹¹ Nm²/kg²
For the Another Planet,
Mass = 4 × Mass of the earth
Mass = 4 × m
Radius = 2 ×Radius of the Earth
= 2 × r
Acceleration due to the Gravity = ng
Now again using the formula,
Acceleration due to gravity = G × Mass/Square of the radius
⇒ ng = G × 4m/(2r)²
ng = G × 4m/4r²
ng = G × m/r² -------------------------------eq(ii)
Putting the Value of g from eq(i) in the above equation,We get,
n × (G × m/r²) = G × m/r²
⇒ n = 1
Thus, the value of n is 1.
→→→→→→→→→→→→
Hope it helps.
Have a Marvelous Day.
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1
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hope it helps u sir ❤❤❤❤❤❤
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