The acceleration due to gravity on the surface of
a planet whose mass is same as that of the Earth
and radius is half of that of the Earth is:
(Mass of Earth = 6 x1024kg and Radius of Earth
= 6.4 x 108 km)
35.08 m/s2
B 39.08 m/s2
28.08 ms
9.08 ms
Please answer
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mass of planet = mass of earth
= 6×1024kg
Radius of planet = half of earth
=6.4×108/2km
=3.4×108km
therefore. g=G.m/r²
g=6.67408×10^-11(6×1024)/ 3.4×108
g=35.08m/s²
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Answer:
The acceleration due to gravity on the surface of
a planet whose mass is same as that of the Earth
and radius is half of that of the Earth is:
(Mass of Earth = 6 x1024kg and Radius of Earth
= 6.4 x 108 km)
35.08 m/s2
B 39.08 m/s2
28.08 ms
9.08 ms
Please answer
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